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Home » You Won’t Believe How This Tie Front Top Transforms Your Outfit—Gallery Inside! - Abbey Badges

You Won’t Believe How This Tie Front Top Transforms Your Outfit—Gallery Inside! - Abbey Badges

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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🔥 Popular Posts

s = \frac{z + 2r + z}{2} = z + r
\frac{\pi r}{z + r}
\boxed{\frac{\pi r}{z + r}}
An equilateral triangle has an area of \( 36\sqrt{3} \) square centime...
The area \( A \) of an equilateral triangle with side length \( s \) i...
Given \( A = 36\sqrt{3} \), we solve for \( s \):
\frac{\sqrt{3}}{4} s^2 = 36\sqrt{3}
s^2 = 144 \quad \Rightarrow \quad s = 12
If each side is decreased by 2 cm, the new side length is \( 10 \) cm....
A' = \frac{\sqrt{3}}{4} \times 10

📝 Recent Posts

We want positive ratio. Try $ y = \frac{-7 + \sqrt{7}}{9} \approx \fra...
Wait — the original assumption about ordering may be wrong. Try symmet...
2a^2 + 18d^2 = 16a^2 \Rightarrow 18d^2 = 14a^2 \Rightarrow \frac{d^2}{...
Third term: $ a + d $, first: $ a - 3d $. Ratio:
\frac{a + d}{a - 3d} = \frac{1 + \frac{d}{a}}{1 - 3\frac{d}{a}}.
Let $ x = \frac{d}{a} $, $ x^2 = \frac{7}{9} \Rightarrow x = \pm \frac...
\frac{1 + \frac{\sqrt{7}}{3}}{1 - \sqrt{7}} = \frac{\frac{3 + \sqrt{7}...
Numerator: $ (3 + \sqrt{7})(1 + \sqrt{7}) = 3 + 3\sqrt{7} + \sqrt{7} +...
Denominator: $ 3(1 - 7) = 3(-6) = -18 $.
So ratio: $ \frac{10 + 4\sqrt{7}}{-18} = -\frac{5 + 2\sqrt{7}}{9} $.

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