DMCA
Contact
Privacy Policy

Home » Why Captain Jack Harkness IS the Most Addictive Villain (and Hero) in TV Right Now! - Abbey Badges

Why Captain Jack Harkness IS the Most Addictive Villain (and Hero) in TV Right Now! - Abbey Badges

📅 February 27, 2026 👤 scraface

Feb 27, 2026

Content is being prepared. Please check back later.

📚 You May Also Like These Articles

📌 \mathbf{w} \times \mathbf{u} = \begin{vmatrix}

📌 & 0 & 1 \\

📌 & 1 & 2 \\

📌 \end{vmatrix} = \mathbf{i}(0 \cdot 2 - 1 \cdot 1) - \mathbf{j}(1 \cdot 2 - 1 \cdot 0) + \mathbf{k}(1 \cdot 1 - 0 \cdot 0) = \langle -1, -2, 1 \rangle

📌 \|\mathbf{w} \times \mathbf{u}\| = \sqrt{(-1)^2 + (-2)^2 + 1^2} = \sqrt{1 + 4 + 1} = \sqrt{6}

📌 Thus, the maximum value of \( |\mathbf{v} \cdot (\mathbf{w} \times \mathbf{u})| \) is \( \sqrt{6} \), achieved when \( \mathbf{v} \) is in the direction of \( \mathbf{w} \times \mathbf{u} \). Since the dot product achieves its maximum absolute value when \( \mathbf{v} \) is aligned with \( \mathbf{w} \times \mathbf{u} \), and \( \|\mathbf{v}\| = 1 \), the maximum is \( \sqrt{6} \).

📌 But the original prompt said "find the largest possible value of", so we compute:

📌 \max_{\|\mathbf{v}\|=1} \left| \mathbf{v} \cdot (\mathbf{w} \times \mathbf{u}) \right| = \|\mathbf{w} \times \mathbf{u}\| = \sqrt{6}

🔥 Popular Posts

Problem:** A journalist analyzing a climate study finds that over 60 d...
Heatwaves: \( 38 \), drought: \( 29 \), both: \( 17 \).
Days with at least one event:
+ 29 - 17 = 50
Total days: 60.
Days with neither:
- 50 = 10
Problem:** A computational ecologist models species presence across tw...
Species in Region A: 54, Region B: 42, common: 19.
Species in either A or B (union):

📝 Recent Posts

Add the 20 grams of salt to the initial amount: \( 20 \text{ g} + 20 \...
Calculate the new total weight of the solution: \( 400 \text{ g} + 20...
Calculate the new percentage of salt: \( \left( \frac{40 \text{ g}}{42...
#### 9.52
A car travels 150 miles at an average speed of 50 mph, then another 20...
Calculate the time for the first part: \( \frac{150 \text{ miles}}{50...
Calculate the time for the second part: \( \frac{200 \text{ miles}}{60...
Find the total distance: \( 150 \text{ miles} + 200 \text{ miles} = 35...
Find the total time: \( 3 \text{ hours} + 3.33 \text{ hours} \approx 6...
Calculate the average speed: \( \frac{350 \text{ miles}}{6.33 \text{ h...

© 2026 Abbey Badges · Powered by WordPress

Disclaimer: This website operates exclusively as an informational archive. Content consists of publicly available international death records, condolence statements, and memorial information. The site does not provide real-time news coverage or entertainment content.