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Home » Step 2: Solve modulo 125 - Abbey Badges

Step 2: Solve modulo 125 - Abbey Badges

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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2x + 3y &= 6 \\
4x - y &= 5
Substitute into the first equation: \(2x + 3(4x - 5) = 6\).
Simplify: \(2x + 12x - 15 = 6\), so \(14x = 21\).
Solve: \(x = 1.5\).
Substitute back to find \(y\): \(y = 4(1.5) - 5 = 1\).
#### \(x = 1.5\), \(y = 1\)
If the sum of the first \(n\) natural numbers is given by \(\frac{n(n+...
Set up the equation: \(\frac{n(n+1)}{2} = 210\).
Multiply by 2: \(n(n+1) = 420\).

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