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5070 ti vs 5080 - Abbey Badges

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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📝 Recent Posts

Question: Compute the square of $ 3\sqrt{2} - 2\sqrt{3} $.
Use the identity $ (a - b)^2 = a^2 - 2ab + b^2 $:
Compute each term:
2(3\sqrt{2})(2\sqrt{3}) = 12\sqrt{6}
Final answer: $ \boxed{30 - 12\sqrt{6}} $
Question: Rationalize the denominator of $ \frac{5}{\sqrt{7} + \sqrt{2...
Multiply numerator and denominator by the conjugate $ \sqrt{7} - \sqrt...
\frac{5}{\sqrt{7} + \sqrt{2}} \cdot \frac{\sqrt{7} - \sqrt{2}}{\sqrt{7...
Simplify the denominator using the difference of squares:
\frac{5(\sqrt{7} - \sqrt{2})}{5} = \sqrt{7} - \sqrt{2}

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